8kelseykuhl 8kelseykuhl

05-04-2018
Mathematics

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[tex]\sqrt{41x^2y^2z^9}[/tex] Please Simplify it!

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altavistard altavistard

12-04-2018

41 is not a perfect square and does not have a perfect square factor. Thus, leave sqrt(41) as is.

sqrt(x^2*y^2) = x*y

sqrt(z^9) = sqrt(z^8*z) = z^4*sqrt(z)

Putting all these factors together, we get sqrt(41)*x*y*z^4*sqrt(z), or

x*y*z^4*sqrt(41z) (answer)

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