vlGunplaylv39 vlGunplaylv39
  • 02-01-2018
  • Physics
contestada

A proton has mass 1.7 ✕ 10−27 kg. what is the magnitude of the impulse required to increase its speed from 0.991c to 0.994c?

Respuesta :

shinmin
shinmin shinmin
  • 15-01-2018
Impulse is the equivalent to the force as the change in momentum, such that F*t = mv - mu 
Since mass and speed is given, use the above right hand side formula mass, m = 1.7 x 10^27 kg initial velocity, u = 0.991 x (3 x 10^8) = 2.973 x 10^8 final velocity, v = 0.994 x (3 x 10^8) = 2.982 x 10^8 
So the computation is:
Impulse = mv - mu 
= [(1.7 x 10^27) x (2.982 x 10^8)] - [(1.7 x 10^27) x (2.973 x 10^8)] = (5.0694 x 10^35) - (5.0694 x 10^35) = 0
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