Pammie123cakess Pammie123cakess

04-06-2014
Mathematics

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how do I solve (3+i)(3-i)

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kate200468 kate200468

04-06-2014

[tex] (3+i)(3-i)=3(3-i)+i(3-i)=9-3i+3i-i^2=9-(-1)=\\\\=9+1=10[/tex]

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05-06-2014

(3+I)(3-1)
-i^2+9=0
-I^2=-9
I^2=9
i= + or - 3

Answer Link

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