Xe = VIII = 8 valence electrons
F = VII = 4 (7 ve) = 28 valence electrons
total ve = 8 + 28 = 36 ve
36 - 4(2) = 28 ve
(there are 2 electrons in each bond x 4 bonds)
28 - 4(6) = 4
(We assign the remaining electrons to F atoms)
4 - 2(2) = 0
(Therefore 4 electrons left => we have 2 lone pairs)
The steric number = No. of
σ bonds + #lone pairs
= 4 σ bonds + 2 lone pairs
= 6 => d²sp³ (6 hybrid orbitals)
4 bonds + 2 lone pairs
=> square planar
