KingjosiahD226322 KingjosiahD226322
  • 04-11-2022
  • Mathematics
contestada

sqrt(-28)write in terms of i

Respuesta :

ParmisG56075 ParmisG56075
  • 04-11-2022

Answer:

[tex]\sqrt[]{-28}=2\sqrt[]{7}i[/tex]

Explanation:

The square roots of negative numbers do not exist on the number line.

This is the reason why there exist, Complex Numbers.

Under this, we have the definition:

[tex]\sqrt[]{-1}=i[/tex]

Given

[tex]\sqrt[]{-28}[/tex]

We can rewrite this as:

[tex]\begin{gathered} \sqrt[]{-1\times28} \\ OR \\ \sqrt[]{-1}\times\sqrt[]{28} \\ =\sqrt[]{-1}\times\sqrt[]{4\times7} \\ \\ =\sqrt[]{-1}\times\sqrt[]{4}\times\sqrt[]{7} \\ =i\times2\times\sqrt[]{7} \\ \\ =2\sqrt[]{7}i \end{gathered}[/tex]

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