ElletP47254 ElletP47254
  • 03-11-2022
  • Mathematics
contestada

Could someone help me out please I don’t know how to

Could someone help me out please I dont know how to class=

Respuesta :

AldrickP226818 AldrickP226818
  • 03-11-2022

As per given by the question,

There are given that ,

[tex]4y^2+y-9,\text{ when y=-3}[/tex]

Now,

There are given y=-3.

So,

Substitute the value -3 instead of y in given equation,

Then,

From the equation,

[tex]4y^2+y-9[/tex]

Put the value of y in given equation,

[tex]4y^2+y-9=4(-3)^2+(-3)-9[/tex]

Now, solve the above equation,

[tex]\begin{gathered} 4y^2+y-9=4(-3)^2+(-3)-9 \\ =4(9)-3-9 \\ =36-3-9 \\ =36-12 \\ =24 \end{gathered}[/tex]

Hence, the value of given equation is 24.

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