fr2ogliluruth fr2ogliluruth
  • 03-12-2016
  • Mathematics
contestada

Find a polynomial function f(n) such that f(1), f(2), ... , f(8) is the following sequence.2, 8, 14, 20, 26, 32, 38, 44

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faiqraees
faiqraees faiqraees
  • 03-12-2016
We can recognize the sequence is an arithmetic progression by noticing that the common difference between each term is 6.
[tex]f(n) = a+(n-1)d[/tex]
where f(n) is the sequence 
n is the term number
d is the common difference 
and a is the starting term

We are well aware that our starting term, and hence a, is 2 and our difference, and hence d, is 6.
So our polynomial function is 
[tex]f(n) = 2+6(n-1)[/tex]

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