Respuesta :

Answer:

50 N

Explanation:

We are given;

Force on larger piston; F2 = 5000 N

Ratio of diameter of smaller piston to larger piston = 1:10

Now, formula for force on smaller piston which we will denote with F1 is gotten from;

F1 = F2 × A1/A2

Now, A1 = π(d1)²/2

A2 = π(d2)²/2

Thus:

F1 = F2 × (π(d1)²/2)/(π(d2)²/2)

This gives;

F1 = F2 × (d1/d2)²

Plugging in the relevant values;

F1 = 5000 × (1/10)²

F1 = 50 N

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