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01-01-2021
Mathematics

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For what value of p the equation [p-3]x²+4[p-3]+4=0

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sufianbaloch4 sufianbaloch4

03-01-2021

Step-by-step explanation:

(p-3)[x²+4]+4=0

(p-3)[x²+4]=-4

(p-3)=-4/x²+4

p=-4/x²+4+3

p=-4+3(x²+4)/x²+4

p= -4+3x²+12/x²+4

p=8+3x²/x²+4

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