katierose675 katierose675
  • 01-10-2020
  • Mathematics
contestada

x + y + z = 9
2x + 3y + z = 16
3x - 4y + 2z = 1​

Respuesta :

LammettHash
LammettHash LammettHash
  • 01-10-2020

Subtract 2(first equation) from the second, and 3(first equation) from the third to eliminate x :

(2x + 3y + z) - 2(x + y + z) = 16 - 2*9

y - z = -2

(3x - 4y + 2z) - 3(x + y + z) = 1 - 3*9

-7y - z = -26

Now subtract either equation with y and z from the other to eliminate z. If we take the first from the second, we get

(-7y - z) - (y - z) = -26 - (-2)

-8y = -24

y = 3

Then

y - z = 3 - z = -2

z = 5

And lastly,

x + y + z = x + 3 + 5 = 9

x = 1

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