marlainarobinson marlainarobinson
  • 04-07-2020
  • Mathematics
contestada

Find the amount in an account where $500 in invested at 2.5% compounded quarterly for a period of 10 years.

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gilbertazavedo72
gilbertazavedo72 gilbertazavedo72
  • 04-07-2020

Answer: $641.51

Step-by-step explanation:

A = p (1+ r/n)^nt

A = 500 (1 + 0.025/4)^4*10

A = 641.51

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abiolataiwo2015
abiolataiwo2015 abiolataiwo2015
  • 05-11-2021

The amount in an account where $500 in invested at 2.5% is $641.51.

Using this formula

A = p (1+ r/n)^nt

Where:

A=Amount

P= Principal=$500

R=Rate=2.5% or 0.025

n=4 (Quarterly)

T=Time=10 years

Let pug in the formula

A = $500(1 + 0.025/4)^4×10

A=$500(1.28302)

A =$641.51

Inconclusion the amount in an account where $500 in invested at 2.5% is $641.51.

Learn more here:

https://brainly.com/question/15380529

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