stardriver1969oybzuw stardriver1969oybzuw

03-04-2020
Mathematics

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(x^2−1)(3x−4)(3x+4) what is the product

Respuesta :

miljanamilovanovic12 miljanamilovanovic12

03-04-2020

Answer:

9x^4-25x^2+16

Step-by-step explanation:

(x^2−1)(3x−4)(3x+4)=(*)

(x^2−1)((3x)^2−4^2) =

(x^2 - 1)(9x^2-16)=

x^2*9x^2 - x^2*16 - 1*9x^2 +16=

9x^4-16x^2-9x^2+16=

9x^4-25x^2+16

(*) (A-B)(A+B) =A^2 - B^2

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