Answer:
The pOH of the solution is 13.176
Explanation:
The concentration of [tex]H_{3}PO_{4}[/tex] solution is 0.05 M
[tex]H_{3}PO_{4}[/tex] produces [tex]3\:H^{+}\:ions\:[/tex].
[tex]H_{3}PO_{4}\longrightarrow3H^{+}+PO_{4}^{3-}[/tex]
If the concentration of [tex]H_{3}PO_{4}[/tex] is 0.05 M, then the concentration of [tex]H^{+}\:ions\:[/tex] is three times that of [tex]H_{3}PO_{4}[/tex].
[tex][H^{+}]=3\times0.05=0.15M[/tex]
pH =-㏒([tex][H^{+}][/tex])= -㏒(0.15) =0.824
pOH = 14 - pH = 13.176
