kdsadrimandylove kdsadrimandylove

01-06-2016
Mathematics

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multiply and simplify.
3x-3/x^2-1* (x+2)(x+1)/x-1

Respuesta :

04-06-2016

Hello,

If x≠1 and x≠-1 then

[tex] \dfrac{3x-3}{x^2-1}*\dfrac{(x+2)(x+1)}{x-1}=\dfrac{3(x-1)}{x-1}*\dfrac{(x+2)(x+1)}{(x-1)(x+1)}\\=\dfrac{3(x+2)}{x+1}[/tex]

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