adrianvxx1252 adrianvxx1252
  • 04-09-2019
  • Physics
contestada

A low-power microprocessor consumes 5 mA at DC. How many electrons flow through the power wiring per second?

Respuesta :

Vespertilio Vespertilio
  • 08-09-2019

Answer:

Explanation:

time, t = 1 second

i = 5 mA = 0.005 A

Charge of one electron, e = 1.6 x 10^-19 C

Charge, q = i t

q = 0.005 x 1 = 0.005 C

Number of electrons in one second = total charge / charge of one electron

[tex]\frac{0.005}{1.6 \times 10^{-19}}=3.125 \times 10^{16}[/tex]

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