maddopresto2000
maddopresto2000 maddopresto2000
  • 01-09-2019
  • Mathematics
contestada

4j^2( - 2j^2+j+2) Don't be late.

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Аноним Аноним
  • 01-09-2019

4j^2( - 2j^2+j+2)

Multiply the bracket by 4j^2

(4j^2)(-2j^2)=-8j^4

(4j^2)(j)=4j^3

(4j^2)(2)=8j^2

-8j^4+4j^3+8j^2

Answer: -8j^4+4j^3+8j^2

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soccerabby11 soccerabby11
  • 01-09-2019

Answer:

[tex]-8j^4+4j^3+8j^2[/tex]

Step-by-step explanation:

Like you said, it's the distributive property.

[tex]4j^2 (-2j^2+j+2)\\ (4j^2*-2j^2) + (4j^2*j) +( 4j^2*2) \\ -8j^4 +4j^3 +8j^2[/tex]

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