doris2002 doris2002

03-01-2019
Mathematics

contestada

How do I work this out?

How do I work this out class=

Respuesta :

LammettHash LammettHash

03-01-2019

We can find the length of BC:

[tex](BC)^2+6^2=12^2\implies BC=6\sqrt3[/tex]

Then by the law of sines,

[tex]\dfrac{\sin55^\circ}{BC}=\dfrac{\sin90^\circ}{CD}\iff CD=\dfrac{6\sqrt3}{\sin55^\circ}\approx12.7\,\mathrm{cm}[/tex]

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