taanaee2455 taanaee2455
  • 03-11-2018
  • Chemistry
contestada

The half-life of cesium-137 is 30 years. Suppose we have a 200-mg sample. (a) Find the mass that remains after t years.

Respuesta :

pbsindhuja
pbsindhuja pbsindhuja
  • 12-11-2018

Given:

Half life(t^ 1/2) :30 years

A0( initial mass of the substance): 200 mg.

Now we know that

A= A0/ [2 ^ (t/√t)]

Where A is the mass that remains after t years.

A0 is the initial mass

t is the time

t^1/2 is the half life

Substituting the given values in the above equation we get

A= [200/ 2^(t/30) ] mg


Thus the mass remaining after t years is [200/ 2^(t/30) ] mg

Answer Link

Otras preguntas

Let's talk about Frankie's work. Does it make sense? Is 3/5 equivalent to 6/10 ? Why or why not? Find at least two other fractions or ratios that are equivalent
Qué ve Nick en uno de los pasillos del castillo
A garden is in the shape of a right triangle with a perimeter of 115 feet. The lengths of the sides of the triangle are each multiplied by 4. What is the perime
4p ≥ -28. What is p?
1) what two numbers multiply to eqaul 12 and ad to eqaul -7?2) what two number multiply to eqaul 64 and eqaul -16?​
Which two reasons explain why the ruling in the Schenck v United States Supreme Court case is significant regarding the First Amendment?
Feed a mouse a death cap mushroom. Two hours later, take out its liver and do RNAseq on it. What would you expect the data to show
Write a short note on MGNREGA-2005​
3/4 (184+t) =237 what is t?
50 Points and Brainliest A student is looking through a microscope at some cells of an onion root tip. Many of these cells are undergoing division since the roo