jsjsa
jsjsa jsjsa
  • 03-09-2018
  • Mathematics
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PLEASE HELP WILL MARK BRAINLIEST!!!!!!!!!!

PLEASE HELP WILL MARK BRAINLIEST class=

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Аноним Аноним
  • 03-09-2018

Given:

[tex] 6x+3y=12 [/tex]

To solve for y, we first need to get y on one side of the equal sign all by itself. To do that, let's start by subtracting 6x from both sides to cancel the +6x on the left. We are then left with:

[tex] 3y=-6x+12 [/tex]

Since we have to solve for y, we can't have the coefficient. So, we need to divide everything by 3.

[tex] \frac{3y}{3}=\frac{-6x}{3}+\frac{12}{3}[/tex]

Simplify.

[tex] y=-2x+4 [/tex]

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madison1025
madison1025 madison1025
  • 03-09-2018
Hope this helps! Message me with any questions :)
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